How to Upload File in Django?

Summary: In this tutorial, you will learn how to handle file upload using model and form in Django framework.

In Django, you can handle file uploads using a model field and the FileField or ImageField field types. Here’s an example:

from django.db import models

class Document(models.Model):
    docfile = models.FileField(upload_to='documents/%Y/%m/%d')

This will define a model with a docfile field that you can use to store and handle uploaded files. The upload_to parameter specifies the directory where the files will be uploaded to.

To handle the actual file upload, you will need to create a form and a view in your Django app. Here’s an example of how you can do that:

# forms.py
from django import forms

class DocumentForm(forms.Form):
    docfile = forms.FileField(
        label='Select a file',
        help_text='max. 42 megabytes'
    )

# views.py
from django.shortcuts import render, redirect
from .forms import DocumentForm

def upload(request):
    if request.method == 'POST':
        form = DocumentForm(request.POST, request.FILES)
        if form.is_valid():
            # handle the file upload
            return redirect('upload_success')
    else:
        form = DocumentForm()
    return render(request, 'upload.html', {'form': form})

Finally, you will need to create an HTML template for the file upload form. Here’s an example of how you can do that:

<!-- upload.html -->
<form method="post" enctype="multipart/form-data">
    {% csrf_token %}
    {{ form.as_p }}
    <input type="submit" value="Upload">
</form>

This will create an HTML form that can be used to upload files. When the form is submitted, the file will be uploaded to the specified directory and the upload view will handle the file upload.