We need to check whether the given matrix is an identity matrix or not using C programming language.
Identity Matrix is a square matrix in which elements in the left diagonal are 1 and all other elements are 0.
Check Identity Matrix in C
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 | #include <stdio.h> #include <stdbool.h> int main() { int matrix[10][10]; int n, i, j; //Initially assuming that the matrix is identity bool flag =true; //Assuming the order of the matrix be n x n printf("Enter the order the matrix \n"); scanf("%d",&n); printf("Enter %d elements in the matrix \n",n); for(i=0; i<n; i++){ for(j=0; j<n; j++){ scanf("%d",&matrix[i][j]); } } printf("Entered Matrix is: \n"); for(i=0; i<n; i++){ for(j=0; j<n; j++){ printf("%d ",matrix[i][j]); } printf("\n"); } //Checking whether the matrix is identity matrix or not for(i=0; i<n; i++){ for(j=0; j<n; j++){ if(i==j && matrix[i][j] != 1){ //Matrix will not be identity matrix if //Diagonal element is not 1 flag = false; break; } else if(i!=j &&matrix[i][j] != 0){ //Matrix will not be identity matrix if //Elements other than diagonal is not 0 flag = false; break; } } } printf("\n"); //line change if(flag) //if(flag == true) printf("Identity Matrix \n"); else printf("Not an Identity Matrix \n"); return 0; } |
Output
In the program we have used a 2D array to represent matrix and for loops to loop through the matrix elements. If you are facing any problem then comment.