Problem: Write a C program to check whether the number is Neon or not.
A number is called a Neon Number if the sum of digits of the square of the number is equal to the original number.
Example: 9
Steps to check neon number in C:
- Input a number.
- Calculate the square of the number.
- Sum digits of the square.
- Check whether the calculated sum is equal to the original number.
- If yes then the number is Neon, else it is not.
Here is the implementation of the steps in C:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | #include <stdio.h> int main() { int num, digit, sum =0; //Input a number printf("Enter a number to check for neon number: \n"); scanf("%d",&num); //Calculate square of the input int square = num*num; //Sum the digits of the square while(square!=0){ digit = square%10; sum += digit; square = square/10; } //Check if sum is equal to the input number if(sum == num) printf("Neon Number \n"); else printf("Not a Neon Number \n"); return 0; } |
Output:
Enter a number to check for neon number:9
Neon Number
To sum up the digits of the square, we have individually extracted each digit using the Modulus operator (i.e. square%10) and added it to the sum variable.
In the end, we compared the calculated sum with the input number num to check whether the given number is a Neon number or not.