Problem: Write a C program to check whether the number is Neon or not.
A number is said to be a Neon Number if the sum of digits of its square is equal to the original number.
Example: 9
Steps to check Neon number in C
- Input a number.
- Calculate the square of the number.
- Sum digits of the square.
- Check if sum of digits of the square is equal to the original number.
- If yes then the number is Neon, else it is not.
Here is the implementation of the steps in C.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | #include <stdio.h> #include <stdlib.h> int main() { int n, digit, sum =0; printf("Enter a number to check for neon Number \n"); scanf("%d",&n); int sq = n*n; while(sq!=0){ digit = sq % 10; sum += digit; sq = sq/10; } if(sum == n) printf("Neon Number \n"); else printf("Not a Neon Number \n"); return 0; } |
Output
In this tutorial, we learned to check Neon Number in C programming language.