Problem: Given a list, find how many times a number is present in the list (i.e frequency) in Python.
Example:
Example 1: Input - [13, 4, 4] Output - [(13, 1), (4, 2)] Example 2: Input - [6, 4, 5, 6, 1, 3, 7, 9, 5, 10, 6] Output - [(1, 1), (3, 1), (4, 1), (7, 1), (9, 1), (10, 1), (5, 2), (6, 3)]
Recommended:
Python Program
def frequency_list(l):
new = []
size = len(l)
while size > 0:
num = l[0]
y=0
c=0
#conting frequency of each element
while y < size and size >=1:
if size ==1:
y=0
if num == l[y]:
index = l.index(num)
l = l[:index] + l[index + 1 :] #removing the element which has already been counted
c+=1
size-=1
else:
y+=1
new.append((num,c)) #appending the (element, count) into list in the form of tupl
return new
Output
print(frequency_list([6,4,5,6,1,3,7,9,5,10,6]))
[(1, 1), (3, 1), (4, 1), (7, 1), (9, 1), (10, 1), (5, 2), (6, 3)]
print(frequency_list([2,10,5,5]))
[(2, 1), (10, 1), (5, 2)]
If you have any suggestion or doubts then comment below.
