Write a Program in Python to convert a decimal number into its corresponding octal representation.
Example:
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Input: 8 Output: 10 Input: 15 Output: 17 |
Recommended:
Convert Decimal to Octal in Python using Loop
The standard way to convert a decimal to octal is to divide the decimal by 8 until it reduces to 0. The remainders in the bottom-up form will give its equivalent octal value.
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decimal = int(input("Enter a decimal number \n")) octal = 0 ctr = 0 temp = decimal #copying number #calculating octal while(temp > 0): octal += ((temp%8)*(10**ctr)) #Stacking remainders temp = int(temp/8) #updating dividend ctr += 1 print("Binary of {x} is: {y}".format(x=decimal,y=octal)) |
Output
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Enter a decimal number 15 Binary of 15 is: 17 |
Convert Decimal to Octal in Python using Recursion
To convert decimal into octal using recursion we need to pass the quotient (dividend/8) to the next recursive call and print the remainder (dividend%8).
Since recursion implements stack so the remainder will be printed in a bottom-up manner.
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def dectoOct(decimal): if(decimal > 0): dectoOct((int)(decimal/8)) print(decimal%8, end='') decimal = int(input("Enter a decimal number \n")) print("Octal: ", end='') dectoOct(decimal); |
Output
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Enter a decimal number 8 Octal: 10 |
Convert Decimal to Octal using oct()
Python inbuilt oct() method return the octal form of a passed number as a parameter.
It returns octal number in the form of 0oxxx, where xxx is the number form of octal representation.
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print(oct(15)) |
Output
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0o17 |
Comment below your doubts or suggestions if you have any.