Write a Program in Python to convert a decimal number into its corresponding octal representation.
Example:
Input: 8 Output: 10 Input: 15 Output: 17
Recommended:
Convert Decimal to Octal in Python using Loop
The standard way to convert a decimal to octal is to divide the decimal by 8 until it reduces to 0. The remainders in the bottom-up form will give its equivalent octal value.
decimal = int(input("Enter a decimal number \n"))
octal = 0
ctr = 0
temp = decimal #copying number
#calculating octal
while(temp > 0):
octal += ((temp%8)*(10**ctr)) #Stacking remainders
temp = int(temp/8) #updating dividend
ctr += 1
print("Binary of {x} is: {y}".format(x=decimal,y=octal))
Output
Enter a decimal number 15 Binary of 15 is: 17
Convert Decimal to Octal in Python using Recursion
To convert decimal into octal using recursion we need to pass the quotient (dividend/8) to the next recursive call and print the remainder (dividend%8).
Since recursion implements stack so the remainder will be printed in a bottom-up manner.
def dectoOct(decimal):
if(decimal > 0):
dectoOct((int)(decimal/8))
print(decimal%8, end='')
decimal = int(input("Enter a decimal number \n"))
print("Octal: ", end='')
dectoOct(decimal);
Output
Enter a decimal number 8 Octal: 10
Convert Decimal to Octal using oct()
Python inbuilt oct() method return the octal form of a passed number as a parameter.
It returns octal number in the form of 0oxxx, where xxx is the number form of octal representation.
print(oct(15))
Output
0o17
Comment below your doubts or suggestions if you have any.
