zip() function in Python combines multiple iterables (list, dict, etc) and returns a list of tuples where each item of the iterables at the same index are paired together.
Let’s see the syntax for zip() function before dipping into examples.
zip(iterables)
zip() parameters
| Parameter | Condition | Description |
| iterables | Required | One or more iterables to be paired together |
Example 1: Same number of Iterables
roll_no = [1, 2, 3] name = ["Abhishek" , "Adarsh", "Chinmay"] student = zip(roll_no, name) student_list = list(student) #Converting iterator to list print(student_list)
output
[(1, 'Abhishek'), (2, 'Adarsh'), (3, 'Chinmay')]
Example 2: Different number of Iterables
roll_no = [1, 2, 3] name = ["Carry" , "Adarsh"] student = zip(roll_no, name) student_list = list(student) #Converting iterator to list print(student_list)
output
[(1, 'Carry'), (2, 'Adarsh')]
You can see that zip() scraped the extra roll number from the list and pairs only the available pair values.
Unzip the Value Using zip()
The * operator in python is used to unzip the zipped list. Follow the example below for a clear explanation.
roll_no = [1, 2, 3]
name = ["Gourav" , "Adarsh", "Pencil Programmer"]
student = zip(roll_no, name)
student_list = list(student) #zipped
#unzipping
r, n = zip(*student_list)
print('roll nos =', r)
print('names =', n)
output
roll nos = (1, 2, 3)
names = ('Gourav', 'Adarsh', 'Pencil Programmer')
If you have any doubts or suggestions regarding the topic then please comment below.