In this python program, we are given a number and we have to **check whether the number is neon** or not.

**Neon Number** is a number whose sum of digits of its square is equal to the original number.

## Steps to Check Neon Number in Python

- Take a
**number as input**. **Find Square**of the number.**Calculate the sum of digits of the square**.- If
**the square is equal to the number, then it is neon number**, else not.

### Neon Number in Python

1 2 3 4 5 6 7 8 9 10 11 12 13 | num = int(input("Enter a number \n")) sqr = num*num #square of num sumOfDigit = 0 #calculating sum of digits of sqr while sqr>0: sumOfDigit =sumOfDigit + sqr%10 sqr = sqr//10 if (num == sumOfDigit): print("Neon Number \n") else: print("Not a Neon Number \n") |

**Language:** Python 3

**Output**

That’s all we need to do, in order to check whether a number is neon or not in python 3. If you have any doubts then comment below.